Question

In peas, yellow seed (Y) is dominant over green seed (y). In this F₂ generation of a monohybrid cross that begins when a dominant homozygote is crossed with a recessive homozygote, you would expect:

Options

• plants that produce three yellow seeds to every green seed

• plants with one yellow seed for every green seed

• only plants with the genotype Yy

• only plants that produce yellow seeds

Answer 1

plants that produce three yellow seeds to every green seed

Explanation:

When a dominant homozygous (YY) pea plant is crossed with a recessive homozygous (yy) plant, all F₁ offspring will be heterozygous (Yy) and display the dominant yellow seed phenotype. When these F₁ plants (Yy) are self-crossed, the F₂ generation shows a typical Mendelian monohybrid 3:1 phenotypic ratio, meaning three plants have yellow seeds for every one plant with green seeds.