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In ΔMPN, MP = 11 cm, PN = 5 cm and MN = 7 cm. Arrange the angles of ΔMPN in ascending order. - Mathematics

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Question

In ΔMPN, MP = 11 cm, PN = 5 cm and MN = 7 cm. Arrange the angles of ΔMPN in ascending order.

Sum
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Solution

We are given sides of ΔMPN:

MP = 11 cm,

PN = 5 cm,

MN = 7 cm

Step 1: Recall the rule

In a triangle, the larger the side, the larger the angle opposite to it.

So to arrange the angles, we compare side lengths.

Step 2: Compare sides 

  • Longest side = MP = 11 → Largest angle opposite = ∠N
  • Next side = MN = 7 → Next angle opposite = ∠P
  • Smallest side = PN = 5 → Smallest angle opposite = ∠M

The angles in ascending order are ∠M < ∠P < ∠N.

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Chapter 9: Inequalities - EXERCISE 9 [Page 102]

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B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 9 Inequalities
EXERCISE 9 | Q 4. | Page 102
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