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Question
In how many ways can 5 different books be arranged on a shelf if there are no restrictions
Sum
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Solution
When there are no restrictions, the 5 books can be arranged in 5P5 ways.
Hence, the required number of arrangements
= 5P5
= 5!
= 5 × 4 × 3 × 2 × 1
= 120
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Chapter 3: Permutations and Combination - Exercise 3.3 [Page 55]
