Question

In the given figure, given that ∆ABC ∼ ∆PQR and quad ABCD ∼ quad PQRS. Determine the value of x, y, z in each case.

Answer 1

We have, `Δ ABCD ∼ Δ PQRS `

So the ratio of the sides of the quadrilaterals will be proportional to each other.

`(AB)/(PQ)=(BC)/(QR)=(CD)/(RS)=(DA)/(SP)`

Therefore put the values of the known terms in the above equation to get,

`20/7=16/x=50/y=50/(3z)`

On solving these simultaneous equations, we get

`x= 28/5`

`y=35/2`

`z=35/6`