Question

In the given figure, given that ∆ABC ∼ ∆PQR and quad ABCD ∼ quad PQRS. Determine the value of x, y, z in each case.

Answer 1

(i) We have,  `Δ ABC ∼ Δ PQR `

So the ratio of the sides of the triangles will be proportional to each other.

`(AB)/(PQ)=(BC)/(QR)=(AC)/(PR)`

Therefore put the values of the known terms in the above equation to get,

`12/9=7/x=10/y`

On solving these simultaneous equations, we get

`x= 21/4`

`y = 30/4`