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Question
In the given figure,
AB || DC prove that
DM × BV = BM ✕ DU
Sum
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Solution
Since ` ∆DMU ∼ ∆BMV`
`(DM)/(BM)=(MU)/(MV)=(DU)/(BV)`
`(DM)/(BM)=(DU)/(BV)`
By cross multiplication, we get `DMxxBVxxDUxxBM`
Hence proved that `DMxxBVxxDUxxBM`
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