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In the Following Verify that the Given Functions (Explicit Or Implicit) is a Solution of the Corresponding Differential Equation:- Y = √ 1 + X 2 Y ' = X Y 1 + X 2 - Mathematics

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Question

In the following verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:-

`y=sqrt(1+x^2)`                     `y'=(xy)/(1+x^2)`

Sum
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Solution

We have,

`y'=(xy)/(1+x^2)   .......... (1)`

Now,

`y=sqrt(1+x^2)`

`rArr y'=x/(sqrt(1+x^2))`

Putting the above value in (1), we get

`"LHS" =x/(sqrt(1+x^2))`

`=x/(sqrt(1+x^2))xxsqrt(1+x^2)/sqrt(1+x^2)`

`=(xy)/(1+x^2)="RHS"`

Thus, `y=sqrt(1+x^2)` is the solution of the given differential equation.

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Chapter 22: Differential Equations - Revision Exercise [Page 144]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 22 Differential Equations
Revision Exercise | Q 3.4 | Page 144

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