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Question
In Fig. AT is a tangent to the circle. If m∠ABC = 50°, AC = BC, Find ∠BAT.
Sum
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Solution
AC = BC
⇒ ∠CBA = ∠CAB
⇒ ∠CAB = 50°
∴ ∠ACB = 180° - (50° + 50°) = 80°
Now, ∠BAT = ∠BCA ....(Angles are in alternate segments)
⇒ ∠BAT = 80°.
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