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In Fig. 10.22, the Sides Ba and Ca Have Been Produced Such That: Ba = Ad and Ca = Ae. Prove that Segment De || Bc.

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Question

In Fig. 10.22, the sides BA and CA have been produced such that: BA = AD and CA = AE.
Prove that segment DE || BC. 

 

 

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Solution

Given that, the sides BA and CA have been produced such that BA =AD  and CA= AE  and
given to prove  DE || BC
Consider triangle BAC and , DAE
We have
BA = ADand CA = AE [∵ given in the data] 
And also ∠BAC=∠DAE [ ∵vertically opposite
angles] 
So, by SAS congruence criterion, we have ΔBAC ≅ ΔDAE
⇒ BC = DE and ∠DEA=∠BCA, ∠EDA ∠CBA
[Corresponding parts of congruent triangles are equal]
Now, DE and BC are two lines intersected by a transversal DB such that ∠DEA =∠BCA,
i.e., alternate angles are equal
Therefore, DE || BC 

 

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Chapter 12: Congruent Triangles - Exercise 12.1 [Page 15]

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R.D. Sharma Mathematics [English] Class 9
Chapter 12 Congruent Triangles
Exercise 12.1 | Q 1 | Page 15

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