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Question
In the circuit shown in the figure, identify the equivalent gate of the circuit and make its truth table.

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Solution

`Y = overline(A'.B') = overline(A') +overline(B') = A+B = `
Truth table
| A | B | `A' =overline(A.A)` | `B' =overline(B.B)` | `Y' =overline(A'.B')` |
| 0 | 0 | 1 | 1 | 0 |
| 0 | 1 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 | 1 |
| 1 | 1 | 0 | 0 | 1 |
Thus the equivalent gate is OR gate.
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Integrated Circuits
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