English

In an ionic crystalline solid atoms of element Y form hcp lattice. The atoms of element X occupy one third of tetrahedral voids. What is the formula of the compound?

Advertisements
Advertisements

Question

In ionic crystalline solid atoms of element Y form hcp lattice. The atoms of element X occupy one-third of tetrahedral voids. What is the formula of the compound?

Sum
Advertisements

Solution

Given: Atoms of element Y form hcp structure.
Atoms of element X occupy 1/3rd of tetrahedral voids

To find: Formula of the compound

Calculation: The atoms of element Y form hcp structure.
The number of tetrahedral voids generated is twice the number of Y atoms.
Thus, number of tetrahedral voids = 2Y
The atoms of element X occupy (1/3) of these tetrahedral voids.
Hence, number of X atoms = 2Y × `1/3 = 2/3"Y"`

Ratio of X and Y atoms = `2/3`Y : 1Y = `2/3`: 1 = 2: 3

∴ Formula of compound = X2Y3 

shaalaa.com
  Is there an error in this question or solution?
Chapter 1: Solid State - Exercises [Page 27]

APPEARS IN

Balbharati Chemistry [English] Standard 12 Maharashtra State Board
Chapter 1 Solid State
Exercises | Q 6 | Page 27

RELATED QUESTIONS

Answer the following in one or two sentences.

Mention two properties that are common to both hcp and ccp lattices.


Answer the following in brief.

Cesium chloride crystallizes in a cubic unit cell with Cl ions at the corners and a Cs+ ion in the center of the cube. How many CsCl molecules are there in the unit cell?


Cu crystallizes in fcc unit cell with edge length of 495 pm. What is the radius of Cu atom?


An element has a bcc structure with a unit cell edge length of 288 pm. How many unit cells and a number of atoms are present in 200 g of the element? (1.16 × 1024, 2.32 × 1024)


Calculate the packing efficiency for bcc lattice.


In case of hcp structure, how are spheres in first, second and third layers arranged?


A compound is formed by elements A and B. This crystallizes in the cubic structure when atoms A are at the comers of the cube and atoms B are at the centre of the body. The simplest formula of the compounds is ____________.


Identify the INCORRECT match.


The vacant space in simple cubic lattice is ____________.


The coordination number of each sphere in simple cubic lattice is ____________.


Which of the following contains the highest number of atoms?


The percentage of vacant space of bcc unit cell is ____________.


What is the edge length of fcc type of unit cell having density and atomic mass 6.22 g cm−3 and 60 g respectively?


1 mol of CO2 contains ____________.


Which of the following is INCORRECT?


Atoms of elements A and B crystallize in hep lattice to form a molecule. Element A occupies 2/3 of tetrahedral voids, the formula of molecule is ______.


What is the percentage of void space in bcc type of in unit cell?


An element crystallizes in a bee lattice with cell edge of 500 pm. The density of the element is 7.5 g cm-3. How many atoms are present in 300 g of metal?


Silver crystallizes in face centred cubic structure, if radius of silver atom is 144.5 pm. What is the edge length of unit cell?


Gold crystallizes in face centred cubic structure. If atomic mass of gold is 197 g mol-1, the mass of unit cell of gold is ______.


AB is an ionic solid. If the ratio of ionic radius of A+ and B- is 0.52, what is the coordination number of B- ?


The relation between the radius of the sphere and the edge length in the body-centred cubic lattice is given by the formula ______.


A compound made of elements C and D crystallizes in a fee structure. Atoms of C are present at the corners of the cube. Atoms of D are at the centres of the faces of the cube. What is the formula of the compound?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×