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In an ac circuit an alternating voltage e = 200√2 sin100t volts is connected to capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is ______.

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Question

In an ac circuit an alternating voltage e = 200\[\sqrt 2\] sin100t volts is connected to capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is ______.

Options

  • 20 mA

  • 10 mA

  • 100 mA

  • 200 mA

MCQ
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Solution

In an ac circuit an alternating voltage e = 200\[\sqrt 2\] sin100t volts is connected to capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is 20 mA.

Explanation:

E = 200\[\sqrt 2\] sin 100 t comparing with E = E0 sin ωt

E0 = 200\[\sqrt 2\] V

ω = 100 rad/s

Irms = \[\frac {E_{rms}}{X_C}\] = \[\frac {E_0}{\sqrt 2}\] × ωC = \[\frac{200\sqrt2}{\sqrt2}\] × 100 × 1 × 10-6 = 20 mA

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