Question

In ∆ABC, ray AD bisects ∠A and intersects BC in D. If BC = a, AC = b and AC = c, prove that \[DC = \frac{ab}{b + c}\].

Answer 1

Since BC = CD + BD

`⇒ CD =BC -BD`

`CD = a - (ac)/(b+c)`

`= (ab)/(b+c)`