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Question
In ΔABC, median AD is produced to E such that AD = DE, prove that ABEC is a parallelogram.
Theorem
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Solution
Given:
In triangle ABC,
AD is a median,
So, D is the midpoint of BC.
AD is produced to E such that AD = DE.
To Prove: ABEC is a parallelogram.
Proof [Step-wise]:
1. From AD being a median
D is the midpoint of BC
⇒ BD = DC
2. Given AD = DE
D is the midpoint of AE
⇒ AD = DE
3. Therefore, D is the midpoint of both BC and AE.
So, the segments BC and AE bisect each other at D.
4. If the diagonals here BC and AE of a quadrilateral bisect each other, the quadrilateral is a parallelogram.
5. Hence, ABEC is a parallelogram since in quadrilateral ABEC, the diagonals AE and BC bisect each other.
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