English

In a ∆Abc, D, E and F Are, Respectively, the Mid-points of Bc, Ca and Ab. If the Lengths of Side Ab, Bc and Ca Are 7 Cm, 8 Cm and 9 Cm, Respectively, Find the Perimeter of ∆Def.

Advertisements
Advertisements

Question

In a ∆ABC, D, E and F are, respectively, the mid-points of BC, CA and AB. If the lengths of side AB, BC and CA are 7 cm, 8 cm and 9 cm, respectively, find the perimeter of ∆DEF.

Advertisements

Solution

Given that

AB = 7cm, BC = 8cm, AC = 9cm .

In  ΔABC

∴ F and E are the midpoint of AB and AC

∴EF = `1/2` BC     [Mid-points theorem]

Similarly

DF = `1/2` AC, DE = `1/2` AB

Perimeter of ΔDEF = DE + EF + DF

= `1/2` AB + `1/2` BC `1/2`AC

= `1/2`× 7 + `1/2` × 8 +` 1 /2`× 9

= 3.5 + 4 + 4.5 = 12cm

Perimeter of ΔDEF = 12cm

shaalaa.com
  Is there an error in this question or solution?
Chapter 13: Quadrilaterals - Exercise 13.4 [Page 62]

APPEARS IN

R.D. Sharma Mathematics [English] Class 9
Chapter 13 Quadrilaterals
Exercise 13.4 | Q 1 | Page 62

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

In below fig. ABCD is a parallelogram and E is the mid-point of side B If DE and AB when produced meet at F, prove that AF = 2AB.


Fill in the blank to make the following statement correct:

The figure formed by joining the mid-points of consecutive sides of a quadrilateral is           


In the given figure, points X, Y, Z are the midpoints of side AB, side BC and side AC of ΔABC respectively. AB = 5 cm, AC = 9 cm and BC = 11 cm. Find the length of XY, YZ, XZ.


In the given figure, ΔABC is an equilateral traingle. Points F, D and E are midpoints of side AB, side BC, side AC respectively. Show that ΔFED is an equilateral traingle.


A parallelogram ABCD has P the mid-point of Dc and Q a point of Ac such that

CQ = `[1]/[4]`AC. PQ produced meets BC at R.

Prove that
(i)R is the midpoint of BC
(ii) PR = `[1]/[2]` DB


D, E, and F are the mid-points of the sides AB, BC, and CA respectively of ΔABC. AE meets DF at O. P and Q are the mid-points of OB and OC respectively. Prove that DPQF is a parallelogram.


In triangle ABC, P is the mid-point of side BC. A line through P and parallel to CA meets AB at point Q, and a line through Q and parallel to BC meets median AP at point R.
Prove that : (i) AP = 2AR
                   (ii) BC = 4QR


In a parallelogram ABCD, M is the mid-point AC. X and Y are the points on AB and DC respectively such that AX = CY. Prove that:
(i) Triangle AXM is congruent to triangle CYM, and

(ii) XMY is a straight line.


In ΔABC, the medians BE and CD are produced to the points P and Q respectively such that BE = EP and CD = DQ. Prove that: Q A and P are collinear.


E is the mid-point of a median AD of ∆ABC and BE is produced to meet AC at F. Show that AF = `1/3` AC.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×