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Question
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is ______.
Options
AD
BE
FC
DE
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Solution
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is BE.
Explanation:
As we know, the median of a triangle bisects the opposite sides.
Hence, the median is BE as AE = EC.
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