Advertisements
Advertisements
Question
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is ______.
Options
AD
BE
FC
DE
Advertisements
Solution
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is BE.
Explanation:
As we know, the median of a triangle bisects the opposite sides.
Hence, the median is BE as AE = EC.
APPEARS IN
RELATED QUESTIONS
The length of hypotenuse of a right angled triangle is 15. Find the length of median of its hypotenuse.
In the given figure, if seg PR ≅ seg PQ, show that seg PS > seg PQ.
In the given figure, point S is any point on side QR of ΔPQR Prove that: PQ + QR + RP > 2PS
Draw an obtuse angled Δ STV. Draw its medians and show the centroid.
The medians of a triangle cross each other at _______
The centroid of a triangle divides each medians in the ratio _______
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If PD = 12, then PN = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If OE = 36 then EP = ?
In a triangle, where is the centroid always located?
Which statement is true about medians?
