Advertisements
Advertisements
Question
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is ______.
Options
AD
BE
FC
DE
Advertisements
Solution
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is BE.
Explanation:
As we know, the median of a triangle bisects the opposite sides.
Hence, the median is BE as AE = EC.
APPEARS IN
RELATED QUESTIONS
In the given figure, point G is the point of concurrence of the medians of Δ PQR. If GT = 2.5, find the lengths of PG and PT.
In the given figure, point S is any point on side QR of ΔPQR Prove that: PQ + QR + RP > 2PS
Draw an obtuse angled Δ LMN. Draw its altitudes and denote the orthocentre by ‘O’.
Draw an isosceles triangle. Draw all of its medians and altitudes. Write your observation about their points of concurrence.
The medians of a triangle cross each other at _______
The centroid of a triangle divides each medians in the ratio _______
The centroid, orthocentre, and incentre of a triangle are collinear
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If PD = 12, then PN = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If DO = 8, then FD = ?
What is a median of a triangle?
