Advertisements
Advertisements
प्रश्न
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is ______.
विकल्प
AD
BE
FC
DE
Advertisements
उत्तर
In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is BE.
Explanation:
As we know, the median of a triangle bisects the opposite sides.
Hence, the median is BE as AE = EC.
APPEARS IN
संबंधित प्रश्न
In the given figure, point G is the point of concurrence of the medians of Δ PQR. If GT = 2.5, find the lengths of PG and PT.
In the given figure, if seg PR ≅ seg PQ, show that seg PS > seg PQ.
Draw an isosceles triangle. Draw all of its medians and altitudes. Write your observation about their points of concurrence.
The centroid of a triangle divides each medians in the ratio _______
Identify the centroid of ∆PQR
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If DE = 44, then DM = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If PD = 12, then PN = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If DO = 8, then FD = ?
In ∆DEF, DN, EO, FM are medians and point P is the centroid. Find the following
If OE = 36 then EP = ?
What is a median of a triangle?
