Question

In a single throw of a die, find the probability that the number:
(i) will be an even number.
(ii) will be an odd number.
(iii) will not be an even number.

Answer 1

A die has six numbers: 1, 2, 3, 4, 5, 6
∴ Number of possible outcome = 6

(i) Number of favourable outcomes = an even number i.e. 2, 4, 6 which are 3 in numbers

∴ P(E) = `"Number of favourable outcome"/"Number of all possible outcome"`

= `3/6 = 1/2`

(ii) & (iii) Number of favourable outcome = not an even number i.e. odd numbers : 1,3,5 which are 3 in numbers

∴ P(E) = `"Number of favourable outcome"/"Number of all possible outcome"`

= `3/6 = 1/2`