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In a region of a uniform electric field E, a negatively charged particle is moving with a constant velocity v = -voi near a long straight conductor coinciding with XX' axis and carrying current I - Physics

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Question

In a region of a uniform electric field `vec E`, a negatively charged particle is moving with a constant velocity `vec v = -v_0 hat i` near a long straight conductor coinciding with XX' axis and carrying current I towards −X axis. The particle remains at a distance d from the conductor.

  1. Draw diagram showing direction of electric and magnetic fields.
  2. What are the various forces acting on the charged particle?
  3. Find the value of vo in terms of E, d and I.
Diagram
Very Long Answer
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Solution

i. The graphical ray diagram illustrating the directions of velocity, electric field, and magnetic field.

Electric and Magnetic Field Directions:

ii. The forces acting on the charged particle include:

  • Electric Force: FE = qE, where q is the charge of the particle.
  • Magnetic Force (Lorentz Force): FB = `q(vec v xx vec B)`, where B is the magnetic field due to the conductor.
  • Gravitational Force: FG = mg, where m is the mass of the particle.

iii. The magnetic field due to the conductor at a distance d is given by:

B = `mu_0 I/(2 pi)`

The Lorentz force acting on the charged particle:

qv0B = qE

`(V_0 mu_0 I)/(2 pi d)` = E

Solving for V0:

V0 = `(2 pi d E)/(mu_0I)`

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2024-2025 (March) Outside Delhi Set 1
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