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Question
In a pseudo first order hydrolysis of ester in water, the following results were obtained:
| t/s | 0 | 30 | 60 | 90 |
| [A]/mol L−1 | 0.55 | 0.31 | 0.17 | 0.085 |
Calculate the average rate of reaction between the time interval 30 to 60 seconds.
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Solution
Average rate of reaction between the time interval, 30 to 60 seconds =
`(C_2 - C_1)/(t_2 - t_1)`
= `(0.17 - 0.31)/(60 - 30)`
= `(0.14)/30`
= -4.67 × 10−3 mol L−1 s−1
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