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In a pool at an aquarium, a dolphin jumps out of the water travelling at 20 cm per second. Its height above water level after t seconds is given by h = 20t – 16t^2.

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Question

In a pool at an aquarium, a dolphin jumps out of the water travelling at 20 cm per second. Its height above water level after t seconds is given by h = 20t – 16t2.

Based on the given information, answer the following questions.

  1. Find the zeros of the polynomial p(t) = 20t – 16t2.
  2. Which of the following types of graphs represents p(t)?
  3. What would be the value of h at `t = 3/2`? Interpret the result.
  4. How much distance has the dolphin covered before hitting the water level again?
Case Study
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Solution

i. \[p(t)=20t-16t^{2}=4t(5-4t)=0\]

\[4t=0 \Rightarrow t=0\]

\[5-4t=0 \Rightarrow t=\frac{5}{4}\]

ii. A quadratic polynomial is represented by a parabola, and its zeros are where the parabola meets the t-axis.

The zeros 0 and `5/4` are consistent with graphs (a) and (c).

The coefficient of t2 is [–16], which is negative, so the parabola opens downward.

Graph (a) is the downward-facing parabola, so it is the correct choice.

iii. \[h=20\left(\frac{3}{2}\right)-16\left(\frac{3}{2}\right)^{2}\]

\[h=30-36=-6 \text{ cm}\]

Interpretation: after `3/2` seconds the dolphin is 6 cm below the water level, which means it has already re-entered the water.

iv. The dolphin returns to the water at `t = 5/4` seconds, so the time of flight is `5/4` s.

\[\text{Distance}=\text{speed}\times\text{time}\]

\[=20\times\frac{5}{4}=25 \text{ cm}\]

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Chapter 20: Additional Questions - Polynomials [Page 975]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 20 Additional Questions
Polynomials | Q 3. | Page 975
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