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In a G.P., a = 2, Tn = 162 and Sn = 242. Find the value of n. - Mathematics

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Question

In a G.P., a = 2, Tn = 162 and Sn = 242. Find the value of n.

Sum
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Solution

`S_n = (r(T_n) - a)/(r - 1)`

242 = `(162r - 2)/(r - 1)`

242(r − 1) = 162r − 2

242r − 242 = 162r − 2

80r = 240

r = `240/80`

r = 3

Tn = a . rn − 1

162 = 2 . 3n − 1

81 = 3n − 1

81 = 34

n − 1 = 4

n = 5

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Chapter 9: Arithmetic and geometric progression - Exercise 9E [Page 199]

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Nootan Mathematics [English] Class 10 ICSE
Chapter 9 Arithmetic and geometric progression
Exercise 9E | Q 12. | Page 199
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