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Question
In a flight of 600 km, an aircraft was slowed due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of the flight increased by 30 minutes. Find the scheduled duration of the flight.
Sum
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Solution
Let the normal Speed of the aircraft be S, and time taken be t.
Distance = 600 km
Time = `"Distance"/"Speed"`
Hence , t = `600/S` ......(i)
And t + 0.5 = `600/(S - 200)` ......(ii)
Puttiing (i) in (ii), we get
`600/(S - 200) - 1/2 = 600/S`
⇒ `(1200 - S + 200)/(2 S - 400) = 600/"S"`
⇒ 1200 S – S2 + 200 S = 1200 S – 2400000
⇒ S2 – 200 S – 240000 = 0
⇒ S2 – 600 S + 400 S – 240000 = 0
⇒ S (S – 600) + 400 (S – 600) = 0
⇒ (S – 600) (S + 400) = 0
Hence, S = 600 km/hr
⇒ T = `600/600` = 1 Hour
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