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Question
In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.
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Solution
Triangle OAB is an equilateral triangle ∠AOB = 60°
= `(60×π)/180 "radians"`
= `π/3` radian
Let arc AB = l
The angle made by the arc at centre O, θ = `π/3` Length of arc AB,
l = rθ = 20 × `π/3` radians
= `(20π)/3` radians
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