Question

In a certain A.P. the 24^th term is twice the 10^th term. Prove that the 72nd term is twice the 34^th term.

Answer 1

Here, we are given that 24^th term is twice the 10^th term, for a certain A.P. Here, let us take the first term of the A.P. as a and the common difference as d

We have to prove that `a_72 = 2a_34`

So, let us first find the two terms.

As we know

`a_n = a + (n - 1)d`

For 10th term (n = 10)

`a_10 = a + (10 - 1)d`

= a + 9d

For 24 th term (n = 24)

`a_24 = a + (24 - 1)d`

= a + 23d

Now we given that `a_24 = 2a_10`

So we get

a + 23d = 2(a + 9d)

a + 23d = 2a + 18d

23d - 18d = 2a - a

5d = a .....(1)

Further, we need to prove that the 72^nd term is twice of 34^th term. So let now find these two terms,

For 34^th term (n = 34),

`a_34 = a + (34 - 1)d`

= 5d + 33d  (Using 1)

= 38d

For 72^nd term (n = 72)

`a_72 = a + (72 - 1)d`

= 5d + 71d     (using 1)

= 76d

= 2(38d)

Therefore `a_72 = 2a_34`