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Question
In a 2-digit number, the digit at the unit's place is 5 less than the digit at the ten's place. The product of the digits is 36. Find the number.
Sum
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Solution
Let the digit in ten's place be x.
Then the one's place digit will be x − 5
The product of two digit = 36
x (x − 5) = 36
x2 − 5x − 36 = 0
⇒ x2 − 9x + 4x − 36 = 0
⇒ (x − 9) (x + 4) = 0
⇒ x = 9, −4
No. = 94
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