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In 2007 – 08, the number of students appeared for Class X examination was 1,05,332 and in 2008 – 09, the number was 1,16,054. If 88,151 students pass the examination in 2007 – 08 - Mathematics

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Question

In 2007 – 08, the number of students appeared for Class X examination was 1,05,332 and in 2008 – 09, the number was 1,16,054. If 88,151 students pass the examination in 2007 – 08 and 103804 students in 2008 – 09. What is the increase or decrease in pass % in Class X result?

Sum
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Solution

Number of students appeared in 2007 – 08 = 105332

Number of students appeared in 2008 – 09 = 116054

Number of students passed in 2007 – 08 = 88151

Number of students passed in 2008 – 09 = 103804

Passed percentage of students in 2007 – 08

= `("Number of students passed in"  2007 - 08)/("Number of students appeared in"  2007 - 08) xx 100`

= `88151/105332 xx 100`

= `8815100/105332`

= 83.68%

Passed percentage of students in 2008 – 09

= `("Number of students passed in"  2008 - 09)/("Number of students appeared in"  2008 - 09) xx 100`

= `103804/116054 xx 100`

= `10380400/116054`

= 89.44%

∴ Increase in percentage = 89.44 – 83.68 = 5.76%

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Chapter 9: Comparing Quantities - Exercise [Page 293]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 9 Comparing Quantities
Exercise | Q 72. | Page 293

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