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If Y = Loge X, Then Find ∆Y When X = 3 and ∆X = 0.03 ?

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Question

If y = loge x, then find ∆y when x = 3 and ∆x = 0.03 ?

Sum
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Solution

We have

\[x = 3\]

\[ ∆ x = 0 . 03\]

\[y = \log_e x\]

\[\text { For } x = 3, \]

\[y = \log_e 3\]

\[\text { Also }, \frac{dy}{dx} = \frac{1}{x}\]

\[ \Rightarrow \left( \frac{dy}{dx} \right)_{x = 3} = \frac{1}{3}\]

\[ \Rightarrow ∆ y = dy = \frac{dy}{dx}dx = \frac{1}{3} \times 0 . 03 = 0 . 01\]

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Chapter 13: Differentials, Errors and Approximations - Exercise 14.2 [Page 12]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 13 Differentials, Errors and Approximations
Exercise 14.2 | Q 2 | Page 12
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