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If Y = a Cos (Loge X) + B Sin (Loge X), Then X2 Y2 + Xy1 = (A) 0 (B) Y (C) −Y (D) None of These - Mathematics

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Question

If y = a cos (loge x) + b sin (loge x), then x2 y2 + xy1 =

Options

  • 0

  • y

  • y

  • none of these

MCQ
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Solution

(c) −y

Here,

\[y = a \cos\left( \log_e x \right) + b \sin\left( \log_e x \right)\]

\[ \Rightarrow y_1 = - a\sin\left( \log_e x \right)\frac{1}{x} + b \cos\left( \log_e x \right)\frac{1}{x}\]

\[ \Rightarrow y_2 = \frac{- a\sin\left( \log_e x \right) + b \cos\left( \log_e x \right)}{x}\]

\[ \Rightarrow y_2 = \frac{- a\cos\left( \log_e x \right) - b \sin\left( \log_e x \right) - \left\{ - a\sin\left( \log_e x \right) + b \cos\left( \log_e x \right) \right\}}{x^2}\]

\[ \Rightarrow x^2 y_2 = - \left\{ a\cos\left( \log_e x \right) + b \sin\left( \log_e x \right) \right\} - \left\{ - a\sin\left( \log_e x \right) + b \cos\left( \log_e x \right) \right\} \]

\[ \Rightarrow x^2 y_2 = - y - x y_1 \]

\[ \Rightarrow x^2 y_2 + x y_1 = - y\]

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Chapter 12: Higher Order Derivatives - Exercise 12.3 [Page 23]

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RD Sharma Mathematics [English] Class 12
Chapter 12 Higher Order Derivatives
Exercise 12.3 | Q 12 | Page 23

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