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If x2 + y2 = t + 1t and x4 + y4 = t2 + 1t2 then dydx = ______

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Question

If x2 + y2 = t + `1/"t"` and x4 + y4 = t2 + `1/"t"^2` then `("d"y)/("d"x)` = ______

Options

  • `x/(2y)`

  • `(-y)/x`

  • `(-x)/(2y)`

  • `y/x`

MCQ
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Solution

`(-y)/x`

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Chapter 2.1: Differentiation - MCQ
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