Question

If x is 30% more than y; find : `("y" + "x")/"x"`

Answer 1

Let y = a

Then x = `"a" xx (100 + 30)/100`

`= "a" xx 130/100 = 13/10 "a"`

Now, `("y" + "x")/"x"`

`= ("a" + 13/10 "a")/(13/10 "a")`

`= ((10 + 13)"a")/(10 xx 13/10 "a")`

`= "23 a"/10 xx 10/"13 a" = 23/13`