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Question
If `x^2 + 1/x^2 = 51, "find" x - 1/x`
Sum
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Solution
Here, `x^2 + 1/x^2 = 51,`
Using the identity:
`(x - 1/x)^2 = x^2 + 1/x^2 - 2`
Substitute the values:
`(x - 1/x)^2` = 51 − 2
`(x - 1/x)^2` = 49
∴ `(x - 1/x) = +-sqrt49`
∴ `(x-1/x) = ±7`
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