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Question
If `|(x + 1, x + 2, x + a),(x + 2, x + 3, x + b),(x + 3, x + 4, x + c)|` = 0, then a, b, care in
Options
A.P
G.P
H.P
None of these
MCQ
Solution
A.P
Explanation:
Apply R1 = R1 + R3 – 2R2
`|(0, 0, a + c - 2b),(x + 2, x + 3, x + b),(x + 3, x + 4, x + c)|` = 0
⇒ a + c – 2b = 0
⇒ a, b, c are in A.P
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