Question

If `|(x + 1, x + 2, x + a),(x + 2, x + 3, x + b),(x + 3, x + 4, x + c)|` = 0, then a, b, care in

पर्याय

• A.P

• G.P

• H.P

• None of these

Answer 1

A.P

Explanation:

Apply R₁ = R₁ + R₃ – 2R₂

`|(0, 0, a + c - 2b),(x + 2, x + 3, x + b),(x + 3, x + 4, x + c)|` = 0

⇒ a + c – 2b = 0

⇒ a, b, c are in A.P