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Question
If `veca` and `vecb` are mutually perpendicular vectors, `|veca + b|` = 13 and `|vecd|` = 5, then find the value of `|vecb|`.
Sum
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Solution
Given:
`veca` ⊥ `vecb` ⇒ `veca.vecb` = 0
|`veca` + `vecb`| = 13
`|veca|` = 5
Assuming `|vecd|` = 5 is a typo for `|veca|` = 5
Using the property `|veca + vecb|^2 = |veca|^2 + |vecb|^2`
⇒ `(13)^2 = (5)^2 + |vecb|^2`
⇒ 169 = 25 + `|vecb|^2` ...[Simplify the squares]
⇒ `|vecb|^2 = 169 − 25`
⇒ `|vecb|^2 = 144`
⇒ `|vecb| = sqrt144`
⇒ `|vecb|` = 12
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