Question

If `vec(AB) = 2hati - 4hatj + 7hatk` and initial point A ≡ (1, 5, 0) then terminal point B is ______.

Options

• (1, 3, 7)

• (7, 3, 1)

• (1, 7, 3)

• (3, 1, 7)

Answer 1

If `vec(AB) = 2hati - 4hatj + 7hatk` and initial point A ≡ (1, 5, 0) then terminal point B is (3, 1, 7).

Explanation:

We know:

`vec(AB) = 2hati - 4hatj + 7hatk`

Initial point

A = (1, 5, 0)

Step 1: Use the formula

`vec(AB) = B - A`

So, `B = A + vec(AB)`

Step 2: Add coordinates

B = (1 + 2, 5 – 4, 0 + 7)

B = (3, 1, 7)