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Question
If two coins are tossed once, what is the probability of getting at least one head.
Sum
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Solution
When two coins are tossed together possible number of outcomes = {HH, TH, HT, TT}
n(S) = 4
E = event of getting at least one head = {HH, TH, HT}
n(E) = 3
Probability of getting at least one head = `(n(E))/(n(S)) = 3/4 `
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