Question

If time of flight of a projectile is 20 seconds. Range is 250 metre. The maximum height attained by it will be ____________.

Options

• 500 m

• 50 m

• 100 m

• 150 m

Answer 1

If time of flight of a projectile is 20 seconds. Range is 250 metre. The maximum height attained by it will be 500 m.

Explanation:

`"T" = (2"u sin"  theta)/"g" = 20  "s" ("Taking g" = 10  "m/s"^2)`

`"u sin"  theta = 100  "m/s"`

`therefore "H" = ("u"^2 "sin"^2 theta)/(2"g") = ("u sin"  theta)^2/(2"g") = (100 xx 100)/(2 xx 10)`

`= 500  "m"`