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प्रश्न
If time of flight of a projectile is 20 seconds. Range is 250 metre. The maximum height attained by it will be ____________.
विकल्प
500 m
50 m
100 m
150 m
MCQ
रिक्त स्थान भरें
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उत्तर
If time of flight of a projectile is 20 seconds. Range is 250 metre. The maximum height attained by it will be 500 m.
Explanation:
`"T" = (2"u sin" theta)/"g" = 20 "s" ("Taking g" = 10 "m/s"^2)`
`"u sin" theta = 100 "m/s"`
`therefore "H" = ("u"^2 "sin"^2 theta)/(2"g") = ("u sin" theta)^2/(2"g") = (100 xx 100)/(2 xx 10)`
`= 500 "m"`
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