Advertisements
Advertisements
Question
If `y = cot^-1((6cotx - 5)/(5cotx + 6)), "then" dy/dx` = ______
Options
1
`1/2`
`-1/2`
-1
MCQ
Fill in the Blanks
Advertisements
Solution
If `y = cot^-1((6cotx - 5)/(5cotx + 6)), "then" dy/dx` = 1.
Explanation:
y = `cot^-1((6/5(cotx) - 1)/(6/5 + cotx))`
= `cot^-1(6/5) + cot^-1(cotx)`
∴ y = `cot^-1(6/5) + x`
∴ `dy/dx = 0 + 1 = 1`
shaalaa.com
Derivative of Inverse Functions
Is there an error in this question or solution?
