Question

If `y = cot^-1((6cotx - 5)/(5cotx + 6)), "then" dy/dx` = ______ 

पर्याय

• 1

• `1/2`

• `-1/2`

• -1

Answer 1

If `y = cot^-1((6cotx - 5)/(5cotx + 6)), "then" dy/dx` = 1.

Explanation:

y = `cot^-1((6/5(cotx) - 1)/(6/5 + cotx))`

= `cot^-1(6/5) + cot^-1(cotx)`

∴ y = `cot^-1(6/5) + x`

∴ `dy/dx = 0 + 1 = 1`