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Question
If the sum of the squares of zeros of the polynomial f(x) = x2 – 8x + k is 40, find the value of k.
Sum
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Solution
Given: Let the zeros be α and β of f(x) = x2 – 8x + k.
Then α + β = 8 and αβ = k.
α2 + β2 = (α + β)2 – 2αβ
= 82 – 2k
= 64 – 2k
Set 64 – 2k = 40 ...(Given)
So, 2k = 24 and k = 12.
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