Advertisements
Advertisements
Question
If the sum of first n terms of an AP is n2, then find its 10th term.
Advertisements
Solution
We know sum of n terms of an AP is
Sn = n2
For n = 1, S1 = (1)2 = 1
So, a1 = 1
For n = 2, S2 = (2)2 = 4
For n = 3, S3 = (3)2 = 9
S2 - S1 = a2
⇒ a2 = 4 - 1 = 3
So, d = a2 - a1 = 3 - 1 = 2
We knopw nth term of an AP is
an = a + (n-1)d
For n = 10
a10 = 1+ (10 - 1)2
⇒ a10 = 1+ 9 × 2
⇒ a10 = 19
Thus, the 10th term of the AP is 19.
APPEARS IN
RELATED QUESTIONS
If the 9th term of an A.P. is zero, then prove that 29th term is double of 19th term.
Find the sum of the following arithmetic series:
`7 + 10 1/2 + 14 + ....... + 84`
Find the 19th term of the following A.P.:
7, 13, 19, 25, ...
Select the correct alternative and write it.
What is the sum of first n natural numbers ?
For a given A.P. a = 3.5, d = 0, then tn = _______.
How many multiples of 4 lie between 10 and 205?
How many two-digit numbers are divisible by 5?
Activity :- Two-digit numbers divisible by 5 are, 10, 15, 20, ......, 95.
Here, d = 5, therefore this sequence is an A.P.
Here, a = 10, d = 5, tn = 95, n = ?
tn = a + (n − 1) `square`
`square` = 10 + (n – 1) × 5
`square` = (n – 1) × 5
`square` = (n – 1)
Therefore n = `square`
There are `square` two-digit numbers divisible by 5
12, 16, 20, 24, ...... Find 25th term of this A.P.
If p - 1, p + 3, 3p - 1 are in AP, then p is equal to ______.
Find a and b so that the numbers a, 7, b, 23 are in A.P.
