Question

If the speed of ultrasound in water is 1600 ms⁻¹ and an impulse sent by the sonar is received by the observer in 3.6 s, then the depth of sea is:

Options

• 2880 m

• 2860 m

• 2840 m

• 2820 m

Answer 1

2880 m

Explanation:

\[ d = \frac{v \times t}{2} \]

\[= \frac{1600 \times 3.6}{2} \]

\[= \frac{5760}{2} \]

= 2880 m