Advertisements
Advertisements
Question
If the replacement set = {- 6,. - 3, 0, 3, 6, 9}; find the truth set of the following : 3x + 7 < 1
Sum
Advertisements
Solution
3x + 7 ≤ 1
⇒ 3x + 7 – 7 ≤ 1 – 7 (Subtracting 7)
⇒ 3x ≤ – 6
⇒ x ≤ – 2
Required Answer = {-6, -3}
shaalaa.com
Replacement Set and Solution Set
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
If the replacement set is the set of natural numbers, solve: x - 5 < 0
If the replacement set is the set of natural numbers, solve: 3x - 4 > 6
If the replacement set is the set of natural numbers, solve: 4x + 1 ≥ 17
Solve : `2/3"x" + 8 < 12; "x" ∈ "W"`
Solve: `-5 ("x" + 4) > 30 ; "x" ∈ "Z"`
Solve the inquation 8 – 2x ≥ x – 5; x ∈ N.
Solve the inequation 18 – 3 (2x – 5) > 12; x ∈ W.
Solve: 4x - 5 > 10 - x, x ∈ {0, 1, 2, 3, 4, 5, 6, 7}.
Solve: 15 – 2(2x – 1) < 15, x ∈ Z.
Solve: `("2x" + 3)/5 > ("4x" - 1)/2`, x ∈ W.
