Advertisements
Advertisements
Question
If the radius of a sphere is measured as 9 m with an error of 0.03 m. the find the approximate error in calculating its surface area
Options
`16 pim^2`
`2.1 pi_m^2`
`2.16 pim^2`
`16.2 pim^2`
MCQ
Solution
`2.16 pim^2`
Explanation:
Radius of the sphere = `9 m`
Error in measurement = `Δr = 0.03 m`
Surface area of sphere S = `4 pir^2`
`Δs = (ds)/(dr) xx Δr = 8 pir xx Δr`
= `8r xx 9 xx 0.03`
= `2.16 pim^2`
shaalaa.com
Is there an error in this question or solution?