Question

If the radius of a sphere is measured as 9 m with an error of 0.03 m. the find the approximate error in calculating its surface area

पर्याय

• `16  pim^2`

• `2.1  pi_m^2`

• `2.16  pim^2`

• `16.2  pim^2`

Answer 1

`2.16  pim^2`

Explanation:

Radius of the sphere = `9  m`

Error in measurement = `Δr = 0.03  m`

Surface area of sphere S = `4 pir^2`

`Δs = (ds)/(dr) xx Δr = 8  pir xx Δr`

= `8r xx 9 xx 0.03`

= `2.16  pim^2`