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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9

If the mean of the following data is 20.2, then find the value of p Marks 10 15 20 25 30 No. of students 6 8 p 10 6

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Question

If the mean of the following data is 20.2, then find the value of p

Marks 10 15 20 25 30
No. of students 6 8 p 10 6
Sum
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Solution

Marks
x
No. of students 
f
fx
10 6 60
15 8 120
20 p 20p
25 10 250
30 6 180
  `sumf` = 30 + p `sumfx` = 610 + 20p

`bar(x) = (sumfx)/(sumf)`

20.2 = `(610 + 20"p")/(30 + "p")`

610 + 20 p = 20.2 ...(30 + p)

610 + 20 p = 606 + 20.2 p

610 – 606 = 20.2 p – 20 p

4 = 0.2 p

p = `4/0.2`

= `(4 xx 10)/2`

= 20

The value of p = 20

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Chapter 8: Statistics - Exercise 8.1 [Page 278]

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Samacheer Kalvi Mathematics [English] Class 9 TN Board
Chapter 8 Statistics
Exercise 8.1 | Q 5 | Page 278

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