Advertisements
Advertisements
Question
If the masses and mutual distance between the two objects are doubled, what is the change in the gravitational force between them?
Advertisements
Solution
By Newton’s law of gravitation
F = `("GM"_1"M"_2)/"r"^2`
Here, the masses and mutual distance between the two objects are doubled.
F = `("G"("M"_1) (2"M"_2))/((2"r")^2) = (4"GM"_1"M"_2)/(4"r"^2)`
F = `("GM"_1"M"_2)/"r"^2`
There is no change in the gravitational force between them.
APPEARS IN
RELATED QUESTIONS
Choose the correct option.
The weight of a particle at the center of the Earth is _______.
The gravitational potential due to the Earth is minimum at _______.
State Newton’s Universal law of gravitation.
Discuss the important features of the law of gravitation.
Explain how Newton verified his law of gravitation.
Assume that you are in another solar system and provided with the set of data given below consisting of the planets’ semi-major axes and time periods. Can you infer the relation connecting semi-major axis and time period?
| Planet (imaginary) | Time period (T) (in year) | Semi-major axis (a) (in AU) |
| Kurinji | 2 | 8 |
| Mullai | 3 | 18 |
| Marutham | 4 | 32 |
| Neithal | 5 | 50 |
| Paalai | 6 | 72 |
If the angular momentum of a planet is given by `vec"L" = 5"t"^2hat"i" - 6"t"hat"j" + 3hat"k"`. What is the torque experienced by the planet? Will the torque be in the same direction as that of the angular momentum?
The escape velocity of a body depends upon mass as ______
The mass density of a spherical galaxy varies as `"K"/"r"` over a large distance 'r' from its center. In that region, a small star is in a circular orbit of radius R. Then the period of revolution, T depends on R as :
Why do planets follow elliptical orbits?
