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Question
If the mass number of a nucleus is doubled, its radius becomes:
Options
2 times
21/3 times
4 times
Unchanged
MCQ
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Solution
21/3 times
Explanation:
\[R=R_{0}A^{1/3}.\mathrm{~If~A\to2A,~then~}R^{\prime}=R_{0}(2A)^{1/3}=2^{1/3}\cdot R.\]
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